1,3483=-0,000004x^2+0,0008x+1,326

Solution for 1,3483=-0,000004x^2+0,0008x+1,326 equation:

1.3483=-0.000004x^2+0.0008x+1.326

We move all terms to the left:

1.3483-(-0.000004x^2+0.0008x+1.326)=0

We get rid of parentheses

0.000004x^2-0.0008x-1.326+1.3483=0

We add all the numbers together, and all the variables

0.000004x^2-0.0008x+0.0223=0

a = 0.000004; b = -0.0008; c = +0.0223;
Δ = b2-4ac
Δ = -0.00082-4·0.000004·0.0223
Δ = 2.832E-7
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.0008)-\sqrt{2.832E-7}}{2*0.000004}=\frac{0.0008-\sqrt{2.832E-7}}{15.7462546277}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.0008)+\sqrt{2.832E-7}}{2*0.000004}=\frac{0.0008+\sqrt{2.832E-7}}{15.7462546277}
$